A science teacher tells her class that their final project requires the student to measure a specific variable and determine the velocity of a car with no more 2.5% error. Jennifer and johnny work hard and decide the velocity of the car is 34.87 m/s. The teacher in forms them that the actual velocity is 34.15 m/s.Will Jennifer and Johnny pass their final project?
34.15 + (.025)34.15 = 34.15 + .85375 = ?
A locomotive train is on its way from Chicago, IL to Madison, WI. The trip is said to last 3.15 hours. When the train arrives in Madison the conductor notices it actually took them 3.26 hours. The train company prides itself on always having its trains to the station within a 3.00% error of the expected time. Will the train company live up to its reputation on this trip?
To determine if Jennifer and Johnny will pass their final project, we need to calculate the percentage error between their measured velocity and the actual velocity.
The percentage error is calculated using the formula:
Percentage Error = |(Measured Value - Actual Value) / Actual Value| * 100%
Let's calculate the percentage error:
Measured Value = 34.87 m/s
Actual Value = 34.15 m/s
Percentage Error = |(34.87 - 34.15) / 34.15| * 100%
Percentage Error = |0.72 / 34.15| * 100%
Percentage Error = 0.0211 * 100%
Percentage Error = 2.11%
The percentage error calculated is 2.11%. Since the requirement is to have no more than a 2.5% error, Jennifer and Johnny will pass their final project because their calculated percentage error is less than the allowed 2.5% error.
To determine if Jennifer and Johnny will pass their final project, we need to compare their measured velocity with the actual velocity and check if the error falls below the threshold allowed by their teacher.
To calculate the error percentage, we can use the following formula:
Error% = ((Measured value - Actual value) / Actual value) x 100
In this case, the measured value is 34.87 m/s, and the actual value is 34.15 m/s.
Substituting these values into the formula:
Error% = ((34.87 - 34.15) / 34.15) x 100
Error% = (0.72 / 34.15) x 100
Error% ≈ 2.11%
The calculated error percentage is 2.11%. Comparing this with the requirement of no more than 2.5% error, we can conclude that Jennifer and Johnny will pass their final project. Their error falls below the allowed threshold, and they have successfully measured the velocity of the car with an acceptable margin of error.