how many ml of a .1M HCl are required to react completely with 1 gm mixture of Na2CO3 ?
What else is in the mixture?
To determine how many ml of a 0.1M HCl solution are required to react completely with 1 gram of Na2CO3, we need to follow these steps:
Step 1: Determine the molar mass of Na2CO3.
The molar mass of Na2CO3 can be calculated by adding up the atomic masses of the elements present in the compound. Na (sodium) has a molar mass of 22.99 g/mol, C (carbon) has a molar mass of 12.01 g/mol, and O (oxygen) has a molar mass of 16.00 g/mol. Since there are two sodium atoms, one carbon atom, and three oxygen atoms in Na2CO3, the molar mass is calculated as follows:
Molar mass of Na2CO3 = (2 * 22.99) + 12.01 + (3 * 16.00) = 105.99 g/mol
Step 2: Calculate the number of moles of Na2CO3.
The number of moles can be calculated using the formula:
Number of moles = Mass of substance / Molar mass
Number of moles of Na2CO3 = 1 g / 105.99 g/mol
Step 3: Determine the balanced equation for the reaction.
The balanced equation between HCl and Na2CO3 is:
2 HCl + Na2CO3 -> 2 NaCl + CO2 + H2O
Step 4: Use the stoichiometry of the balanced equation to determine the number of moles of HCl required.
From the balanced equation, it can be seen that 2 moles of HCl react with 1 mole of Na2CO3. Therefore, the number of moles of HCl required can be calculated as follows:
Number of moles of HCl = (Number of moles of Na2CO3) * (2 moles of HCl / 1 mole of Na2CO3)
Step 5: Calculate the volume of the HCl solution required.
The concentration of the HCl solution is given as 0.1M, which means there are 0.1 moles of HCl in 1 liter of solution. To calculate the volume of HCl solution required, we can use the following formula:
Volume of HCl solution (in liters) = (Number of moles of HCl) / (Concentration of HCl)
Step 6: Convert the volume to milliliters (ml).
Finally, multiply the volume of HCl solution in liters by 1000 to convert it to milliliters (ml) since 1 liter is equal to 1000 milliliters.
By following these steps, you can determine the number of milliliters of a 0.1M HCl solution required to react completely with 1 gram of Na2CO3.