5.Mrs.Sandoval has 60 folders, 45 scissors, and 30 rulers. What is the largest number of equally divided school supply groups Mrs.Sandoval can create without any remaining supplies?

A.5
B.10
C.3
D.15
D

6.What is the prime factorization of 550?
A.2x5^2x11

7.What is the value of the expression below
12-6x2/4+1
10

8.Mr.Perry bought a computer for $1920 including tax. If he pays it in 16 equal payments what will be the dollar amount of each payment
120?

All are correct.

To find the largest number of equally divided school supply groups Mrs.Sandoval can create without any remaining supplies, we need to find the greatest common divisor (GCD) of the numbers 60, 45, and 30.

The GCD of 60, 45, and 30 is 15.

Therefore, Mrs.Sandoval can create 15 equally divided school supply groups without any remaining supplies.

So the correct answer is D. 15.

Next question:

To find the prime factorization of 550, we need to factorize it into its prime factors.

The prime factorization of 550 is 2 × 5^2 × 11.

So the correct answer is A. 2 × 5^2 × 11.

Next question:

To find the value of the expression 12 - 6 × 2 ÷ 4 + 1, we need to follow the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

12 - 6 × 2 ÷ 4 + 1

First, we perform the multiplication and division from left to right:

12 - 12 ÷ 4 + 1

Next, we perform the addition and subtraction from left to right:

12 - 3 + 1

Finally, we perform the subtraction:

12 - 3 = 9

So the value of the expression is 9.

Next question:

To find the dollar amount of each payment if Mr.Perry pays $1920 in 16 equal payments, we need to divide the total amount by the number of payments.

$1920 ÷ 16 = $120

Therefore, the dollar amount of each payment will be $120.

So the correct answer is $120.

To find the largest number of equally divided school supply groups Mrs. Sandoval can create without any remaining supplies, we need to find the greatest common divisor (GCD) of the quantities of folders, scissors, and rulers.

Step 1: Find the GCD of 60 and 45.
- List the factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
- List the factors of 45: 1, 3, 5, 9, 15, 45.
- The largest number that both lists have in common is 15.

Step 2: Find the GCD of the result from step 1 (15) and 30.
- List the factors of 15: 1, 3, 5, 15.
- List the factors of 30: 1, 2, 3, 5, 6, 10, 15, 30.
- The largest number that both lists have in common is 15.

Therefore, the largest number of equally divided school supply groups Mrs. Sandoval can create without any remaining supplies is 15.

For the prime factorization of 550, we need to break it down into its prime factors.

Step 1: Divide 550 by the smallest prime number, 2.
550 ÷ 2 = 275

Step 2: Divide the result (275) by the smallest prime number, 5.
275 ÷ 5 = 55

Step 3: Divide the result (55) by the smallest prime number, 5.
55 ÷ 5 = 11

Now, we have reached a prime number (11).

Therefore, the prime factorization of 550 is 2 × 5 × 5 × 11, which can be simplified as 2 × 5^2 × 11.

To evaluate the value of the expression 12 - 6 × 2 ÷ 4 + 1, we follow the order of operations (also known as PEMDAS/BODMAS).

Step 1: Calculate 6 × 2 = 12.
Step 2: Calculate 12 ÷ 4 = 3.
Step 3: Substitute the results into the expression: 12 - 3 + 1.
Step 4: Calculate 12 - 3 = 9.
Step 5: Calculate 9 + 1 = 10.

Therefore, the value of the expression is 10.

To find the dollar amount of each payment for Mr. Perry's computer purchase, we divide the total cost ($1920) by the number of payments (16).

$1920 ÷ 16 = $120.

Therefore, the dollar amount of each payment will be $120.