precalc

verify the identity

((cosxcotx)/(1-sinx))-1=cscx

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  1. ((cosxcotx)/(1-sinx))-1=cscx

    (cos x*cos x/sin x) /(1-sin x) = 1 + 1/sin x

    (cos^2 x)/[sin x *(1-sin x)] = (sin x+1)/sin x

    cos^2 x/(1-sin x) = (1 + sin x)

    cos^2 x = (1-sin x)(1+sin x)

    cos^2 x = 1 - sin^2 x
    sure does

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    posted by Damon

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