How much energy would be released when 675 grams of steam is condensed to water
q = mass steam x heat condensation
To calculate the amount of energy released when steam is condensed to water, you will need to use the equation:
Q = m * ΔH
where:
Q is the energy released (in joules),
m is the mass of steam (in grams), and
ΔH is the enthalpy change (in J/g) for the phase transition from steam to water.
The enthalpy change for the phase transition from steam to water is known as the heat of vaporization. For water, the heat of vaporization is approximately 2260 J/g.
First, convert the mass of steam from grams to kilograms:
675 grams = 675/1000 = 0.675 kg
Next, substitute the values into the equation:
Q = (0.675 kg) * (2260 J/g)
= 1525.5 J
Therefore, approximately 1525.5 joules of energy would be released when 675 grams of steam is condensed to water.