1)I AM greater than 15 and less than 40 if you double me I become a number that ends in 0 1/5 of me is equal to 5
2) if you multiply me by 2 ,I become a number greater than 20 and less than 40 if you multiply me by 6,I end in 8 if you multiply me by 4 I end in 2
Help me figure out who I am
1) 25
1/5x = 5
x = 5*5
x = 25
2)18
It states that when it is multiplied by 2 it is between 20 and 40 so divide both 20 and 40 by 2 and that shows that your range of numbers is between 10 and 20.
18*2 = 36 between 20 and 40
18*6 = 108
18 * 4 = 72
1)
(1/5)x = 5
x = ?
2)
From the first clue the number must be between 11 and 19
Take it from there.
To solve this problem, we need to find a number that satisfies all the given conditions.
1) I AM greater than 15 and less than 40.
Let's start by finding a number within this range. One possible number is 20.
2) If you double me, I become a number that ends in 0.
If we double 20, we get 40, which ends in 0. This condition is satisfied.
Next, let's figure out the other conditions:
1/5 of me is equal to 5.
To find 1/5 of a number, we divide it by 5. Dividing 20 by 5 gives us 4. This condition is satisfied as well.
Therefore, the answer to the first question is 20.
Now let's move on to the second question.
1) If you multiply me by 2, I become a number greater than 20 and less than 40.
Let's start by finding a number within this range. One possible number is 21.
2) If you multiply me by 6, I end in 8.
Multiplying 21 by 6 gives us 126, which does not end in 8. So 21 does not satisfy this condition.
3) If you multiply me by 4, I end in 2.
Multiplying 21 by 4 gives us 84, which ends in 4, not 2. So again, 21 does not satisfy this condition.
Since 21 does not satisfy all the given conditions, we need to try another number between 20 and 40.
Let's try 22.
1) Multiplying 22 by 2 gives us 44, which is greater than 20 and less than 40. This condition is satisfied.
2) Multiplying 22 by 6 gives us 132, which ends in 2. This condition is satisfied.
3) Multiplying 22 by 4 gives us 88, which ends in 8. This condition is also satisfied.
Therefore, the answer to the second question is 22.
So, the number you are looking for is 22.