How much work is done pushing a wheel barrow full of cement 5.3m forward if a force of 500N is applied 20 degrees from the vertical?
Work = Fx*d = 500*cos20*5.3 = 2490 J.
To calculate the work done, we can use the formula:
Work (W) = Force (F) * Distance (d) * cos(theta)
where:
- Work is measured in joules (J),
- Force is measured in newtons (N),
- Distance is measured in meters (m), and
- Theta is the angle between the direction of force and the direction of displacement.
In this case, we have:
Force (F) = 500N
Distance (d) = 5.3m
Theta (θ) = 20 degrees
First, let's convert the angle from degrees to radians:
Theta (θ) = 20 degrees * (π/180) = 0.3491 radians (approximately)
Next, we can calculate the work done using the formula mentioned above:
Work (W) = 500N * 5.3m * cos(0.3491)
= 500N * 5.3m * 0.9397 (cosine of 0.3491 radians)
≈ 2505 J (rounded to the nearest whole number)
Therefore, the work done in pushing the wheelbarrow is approximately 2505 joules (J).