if an electric kettle of 5ooW power and water in it,is heated.the temperature change from10-15c for 100 sec.find the heat capacity

To find the heat capacity, we need to calculate the amount of heat energy transferred.

The formula for heat energy is:

Q = m * c * ΔT

Where:
Q = heat energy transferred (in joules)
m = mass of the substance (in kilograms)
c = specific heat capacity of the substance (in joules per kilogram per degree Celsius)
ΔT = change in temperature (in degrees Celsius)

In this case, the water in the electric kettle is being heated, so the specific heat capacity of water is required. The specific heat capacity of water is approximately 4.18 joules per gram per degree Celsius (4.18 J/g°C) or 4186 joules per kilogram per degree Celsius (4186 J/kg°C).

First, let's convert the power of the electric kettle to energy:

P = 500 watts (or 500 joules per second)
t = 100 seconds
E = P * t = 500 * 100 = 50000 joules

Next, we need to find the mass of the water. Since we don't have the mass, we can assume it to be 1 kilogram.

Using these values, we can now calculate the heat capacity:

Q = m * c * ΔT
50000 = 1 * 4186 * (15 - 10)
50000 = 20930

Therefore, the heat capacity would be 20930 J or 20.93 kilojoules (kJ).