How many g of NaOH are in 10 ml 0.1 M solution?

How do you find this out, what are the steps?

To find out how many grams of NaOH are in a 10 ml 0.1 M (molar) solution, you need to use the molarity and molar mass of NaOH. Here are the steps to calculate it:

Step 1: Determine the molar mass of NaOH.
The molar mass of NaOH can be calculated by adding the atomic masses of sodium (Na), oxygen (O), and hydrogen (H). The atomic masses are:
Na = 22.99 g/mol
O = 16.00 g/mol
H = 1.01 g/mol

So, the molar mass of NaOH is:
Na = 22.99 g/mol
O = 16.00 g/mol
H = 1.01 g/mol

Molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 39.99 g/mol

Step 2: Determine the number of moles in the solution.
To find the number of moles in the 10 ml 0.1 M solution, you need to multiply the molarity (0.1 M) by the volume (10 ml) and convert it to liters:
Molarity = 0.1 mol/L
Volume = 10 ml = 10/1000 L = 0.01 L

Number of moles = Molarity x Volume = (0.1 mol/L) x (0.01 L) = 0.001 mol

Step 3: Convert moles to grams.
To convert moles to grams, you multiply the number of moles by the molar mass:
Number of grams = Number of moles x Molar mass = (0.001 mol) x (39.99 g/mol) = 0.03999 g

So, there are approximately 0.04 grams of NaOH in a 10 ml 0.1 M solution.