n inspector correctly identifies defective products 90% of the time. For the next 10 products, what is the probability that he makes fewer than 2 incorrect inspections? Note: Please report your answer with two places to the right of the decimal, rounding if appropriate.

Question

n inspector correctly identifies defective products 90% of the time. For the next 10 products, what is the probability that he makes fewer than 2 incorrect inspections? Note: Please report your answer with two places to the right of the decimal, rounding if appropriate.

Answer 1

Use the binomial probability function:

P(x) = (nCx)(p^x)[q^(n-x)]

n = 10
x = 0,1
p = 0.10
q = 1 - p = 0.90

Find P(0), P(1). Add together for your probability.

Note:
You can also use a binomial probability function table with the values listed to find the probability as well. It is an easier way of doing this problem.

I hope this will help get you started.