I have two problems that I am not sure about how to work out.
1. The distance traveled by a falling object is given by the formula d=4.9t^2, where d is in meters and t is in seconds. Solve the formula for t.
2.The volume of a right circular cone is given by the formula V=1/3(pi)r^2h. Solve the formula for r in terms of V and h.
d = 4.9t^2
get what you are solving for on one side and put everything else on the other side.
Do that by simple algebra.
Divide both sides by 4.9
d/4.9 = t^2
now take the square root of both sides.
sqrt(d/4.9) = square root (t^2)= +/-t.
You do the second one the same way.
THANKS WE HAVEN'T DONE THOSE PROBLEMS ALL YEAR!
1. To solve the formula for t, we need to isolate the variable t.
The given formula is: d = 4.9t^2
Step 1: Divide both sides of the equation by 4.9 to isolate t^2:
d/4.9 = t^2
Step 2: Take the square root of both sides to solve for t:
√(d/4.9) = t
Therefore, the solution for t is t = √(d/4.9).
2. To solve the formula for r in terms of V and h, we need to isolate the variable r.
The given formula is: V = (1/3)πr^2h
Step 1: Multiply both sides of the equation by 3 to isolate the fraction:
3V = πr^2h
Step 2: Divide both sides of the equation by πh to solve for r^2:
(3V) / (πh) = r^2
Step 3: Take the square root of both sides to solve for r:
√[(3V) / (πh)] = r
Therefore, the solution for r is r = √[(3V) / (πh)].