the perimeter of a basketball court is 268 feet. the area is 4200 ft2. find the dimensions. using quadratics
let the width be x
and the length y
2(x+y) = 268
x+y = 134
y = 134-x
xy = 4200
x(134-x) = 4200
134x - x^2 - 4200=0
x^2 - 134x + 4200 = 0
(x - 50)(x - 84) = 0
x = 50 or x = 84
if x = 50 , then y = 134-50 = 84
if x = 84, y = 50
the rectangle is 50 by 84