Answer the following quadratic function
f(x)= x^2 + 6x - 16
What is the axis of symmetry?
find the vertex
You should get (-3 , -25)
so the axis of symmetry is x = -3
To find the axis of symmetry of a quadratic function in the form of f(x) = ax^2 + bx + c, you can use the formula -b/2a.
In the given function f(x) = x^2 + 6x - 16, we have a = 1 and b = 6.
Substituting these values into the formula, we find the axis of symmetry as follows:
Axis of symmetry = -b/2a
= -6/(2*1)
= -6/2
= -3
Therefore, the axis of symmetry for the given quadratic function is x = -3.