Two point charges, +3.27 µC and -6.15 µC, are separated by 1.08 m. What is the electric potential midway between them?

To find the electric potential midway between two point charges, we can use the equation for electric potential due to a point charge.

The equation for electric potential due to a point charge is given by:

V = k * Q / r

Where:
V is the electric potential
k is the Coulomb's constant (k = 8.99 * 10^9 Nm^2/C^2)
Q is the charge of the point charge
r is the distance from the point charge

In this case, we have two point charges:
Charge 1: +3.27 µC
Charge 2: -6.15 µC

We need to find the electric potential midway between them, which means the distance from each charge to the point where we are measuring is the same. Suppose the distance is 'd'.

Given:
Charge 1: Q1 = +3.27 µC
Charge 2: Q2 = -6.15 µC
Distance from each charge to the midpoint: d = 1.08 m / 2 = 0.54 m

Now, let's calculate the electric potential due to each charge separately:
For Charge 1: V1 = (8.99 * 10^9 Nm^2/C^2) * (3.27 * 10^-6 C) / (0.54 m)
For Charge 2: V2 = (8.99 * 10^9 Nm^2/C^2) * (-6.15 * 10^-6 C) / (0.54 m)

Finally, to find the electric potential midway between them, we can add the potentials due to each charge together:
V_midpoint = V1 + V2

Calculate V1:
V1 = (8.99 * 10^9 Nm^2/C^2) * (3.27 * 10^-6 C) / (0.54 m) = 54.23 V

Calculate V2:
V2 = (8.99 * 10^9 Nm^2/C^2) * (-6.15 * 10^-6 C) / (0.54 m) = -102.38 V

Add V1 and V2 together:
V_midpoint = V1 + V2 = 54.23 V + (-102.38 V) = -48.15 V

Therefore, the electric potential midway between the two point charges is -48.15 V.