How do you find the domain of a function when the number is outside of the paranthesese. Example would be

y=(square root of x)+3. I know that to find the domain when the number is under the square root, you have to make the number greater than or equal to zero and then add or subtract accordingly. Example would be y=(square root of x + 2), the domain would be -2.

I already answered this

To find the domain of a function, you need to consider any restrictions on the variable(s) of the function. In this case, you are given the function y = √x + 3.

For the domain, the square root function (√) needs to have a non-negative value within the parentheses. As you correctly mentioned, when the number under the square root is outside of any parentheses, you need to consider the entire expression as the argument of the square root.

So for y = √x + 3, the domain will be determined by the condition that the expression inside the square root (√x + 3) must be non-negative:

√x + 3 ≥ 0

To solve this inequality, we need to isolate x. First, we subtract 3 from both sides:

√x ≥ -3

Next, we square both sides (since squaring a non-negative number leaves the inequality direction unchanged):

x ≥ (-3)^2

which simplifies to:

x ≥ 9

Therefore, the domain of the function y = √x + 3 is x ≥ 9. This means that the function is defined for all x-values greater than or equal to 9.