comment that enthalpy of nutralization is merely the heat of formation one-one mole of liquid water
The enthalpy of neutralization refers to the heat energy released or absorbed when an acid and a base react to form one mole of water. It is often expressed as the heat of reaction per mole of water formed.
Now, let me explain why the enthalpy of neutralization can be considered as the heat of formation of one mole of liquid water.
To determine the enthalpy of neutralization, you can follow these steps:
1. Look up the standard enthalpies of formation for the acid, the base, and the product (water, in this case). These values represent the heat energy released or absorbed when one mole of a substance is formed from its constituent elements in their standard states.
2. Find the balanced chemical equation for the neutralization reaction between the acid and the base.
3. Apply the law of conservation of energy, also known as Hess's Law. According to this law, the overall enthalpy change of a reaction is independent of the pathway taken.
4. Based on the balanced chemical equation, determine the stoichiometry of the reaction. For every mole of water formed, there should be one mole of acid and one mole of base reacting.
5. Subtract the sum of the standard enthalpies of formation of the acid and the base from the standard enthalpy of formation of water. This will give you the heat of neutralization per mole of water formed.
6. Remember to consider the sign of the enthalpy change (positive or negative) to indicate whether the reaction is exothermic or endothermic. If heat is released to the surroundings, the reaction is exothermic and the enthalpy change is negative. If heat is absorbed from the surroundings, the reaction is endothermic and the enthalpy change is positive.
So, to summarize, the enthalpy of neutralization can be regarded as the heat of formation of one mole of liquid water, but it involves considering the standard enthalpy of formation for both the acid and the base as well.