what volume will be occupied by 3.25mol of oxygen gas at 735mmhg and 25celcius?
Note how to spell celsius.
Note that you start sentences with a capital letter. Don't try to make this a texting board.
Use PV = nRT. n = 3.25. Remember that T MUST be in kelvin and P should be in atmospheres.
735 mm Hg = 735/760 atm.
To calculate the volume occupied by a gas, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure of the gas (in atm)
V = volume of the gas (in liters)
n = number of moles of the gas
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature of the gas (in Kelvin)
First, we need to convert the given temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
So, T(K) = 25 + 273.15 = 298.15 K
Next, we need to convert the given pressure from mmHg to atm:
P(atm) = P(mmHg) / 760
P(atm) = 735 / 760 = 0.967 atm
Now we have all the values we need, so we can rearrange the ideal gas law equation to solve for V:
V = (nRT) / P
V = (3.25 mol * 0.0821 L.atm/mol.K * 298.15 K) / 0.967 atm
Calculating the above expression will give us the volume occupied by 3.25 mol of oxygen gas at 735 mmHg and 25 °C.