A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r = 0.12 m. The normal to the plane of the loop is parallel to a constant magnetic field ( = 0°) of magnitude 0.85 T. What is the change ÄÖ in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?
ÄÖ = V
How can I possibly know what is in the drawing?
To find the change in magnetic flux, we can use Faraday's Law of Electromagnetic Induction. According to Faraday's law, the change in magnetic flux through a loop is equal to the induced electromotive force (emf) in the loop. The equation for Faraday's law is:
ΔΦ = -N dΦ/dt
Where:
ΔΦ is the change in magnetic flux
N is the number of turns in the loop
dΦ/dt is the rate of change of magnetic flux through the loop
In this case, we are given that the normal to the plane of the loop is parallel to the constant magnetic field. This means that the magnetic flux passing through the loop is constant, and there is no change in magnetic flux. Therefore, the change in magnetic flux (ΔΦ) is zero.
So, in this situation, the change in magnetic flux (ΔΦ) is equal to zero.