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Mathematics
Sets
Counting or Number Theory
How many elements are in the set {10,12,14,…,48,50}?
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21
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Suppose Set B contains 69 elements and the total number elements in either Set A or Set B is 107. If the Sets A and B have 13
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Sets A and B have 13 elements in common. The total of their union is 107. But this 107 only accounts
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Suppose Set B contains 69 elements and the total number elements in either Set A or Set B is 107. If the Sets A and B have 13
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A+69-13 = 107
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Suppose Set B contains 69 elements and the total number elements in either Set A or Set B is 107. If the Sets A and B have 13
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Union is 107 Intersection is 13 draw Venn diagram 69 + A alone = 107 so A alone = 38 plus A and B =
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Let the Universal Set, S, have 136 elements. A and B are subsets of S. Set A contains 34 elements and Set B contains 98
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34-22
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The numbers 1,2,…,17 are divided into 5 disjoint sets. One set has 5 elements, one set has 4 elements, two sets have 3
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Hmmm. For each set of size n, there's a n/17 chance that each person picked a number from that set.
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The numbers 1,2,…,17 are divided into 5 disjoint sets. One set has 5 elements, one set has 4 elements, two sets have 3
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probability is from 0 to 1. No way it can be expressed as the product of integers.
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For the set X={m,n.p,q,r,s}, let R be the relation on P(X) (power set) given by A R B iff A and B have the same number of
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List the following elements in proper set notation. Place the elements in numerical order within the
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S, have 176 elements. A and B are subsets of S. Set A contains 71 elements and Set B contains 80 elements. If Sets A and B have
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You have a total of 71+80-11 = 140 in A and B So, 36 are in neither.
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Sets $A$ and $B$, shown in the Venn diagram, are such that the total number of elements in set $A$ is twice the total number of
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Let $A$ have $x$ elements and $B$ have $y$ elements. We are given that $x = 2y$. Also, we are given
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A subset of a given set may contain no elements, all the elements of the given set, or some of the elements of the given set.
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1 + 7 + 2 (7C2 + 7C3) + 7 + 1
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