Find the vertex of the parabola.
y = -2x2 + 12x - 13
Use the equation vertex=-b/2a.
b would be 12
a would be -2
That gets you the x value of the vertex, which is 3. Plug in 3 for x now to get y.
y=-2(3)^2+12(3)-13
y=36+36-13
y=59.
Your vertex is (3,59).
To find the vertex of a parabola in the form `y = ax^2 + bx + c`, you can use the following formula:
x-coordinate of the vertex = -b / (2a)
For the given equation `y = -2x^2 + 12x - 13`, the coefficient `a` is -2 and the coefficient `b` is 12. Plugging these values into the formula, we get:
x-coordinate of the vertex = -12 / (2 * -2) = -12 / -4 = 3
To find the y-coordinate of the vertex, substitute the x-coordinate back into the equation:
y = -2(3)^2 + 12(3) - 13
= -18 + 36 - 13
= 5
Therefore, the vertex of the parabola is at (3, 5).