If 22.0 of gas has a volume of 0.22 at 320 , what is its pressure in mmHg?
sorry that ssupposed to say 320 K
To find the pressure of the gas, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant
T = temperature of the gas in Kelvin
Given:
V = 0.22 L
n = 22.0 mol
T = 320 K
First, we need to convert the volume from liters to m^3 and the pressure to Pascals:
1 L = 0.001 m^3
1 atm = 101325 Pa
Converting the volume:
V = 0.22 L * 0.001 m^3/L
V = 0.00022 m^3
Converting the pressure:
P = x mmHg * 101325 Pa/mmHg
P = x * 101325 Pa
Now we can rearrange the ideal gas law equation to solve for P:
PV = nRT
P = nRT / V
Substituting the given values:
P = (22.0 mol * 8.314 J/(mol*K) * 320 K) / 0.00022 m^3
Calculating the pressure in Pascals:
P = 2406400 Pa
Converting the pressure to mmHg:
2406400 Pa * (1 mmHg / 133.322 Pa)
P = 18030 mmHg
Therefore, the pressure of the gas is 18030 mmHg.
To find the pressure in mmHg, we need to use the ideal gas law equation: PV = nRT, where P represents the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
In this case, we need to rearrange the equation to solve for the pressure:
P = (nRT)/V
Given:
Volume (V) = 0.22 L
Amount of gas (n) = 22.0 mol
Temperature (T) = 320 K (Kelvin)
First, we need to convert the volume of the gas from Liters to m³, since the ideal gas constant (R) is typically given in units of m³•Pa/(mol•K):
V = 0.22 L = 0.22 * 0.001 m³ = 0.00022 m³
Next, we can plug in the values into the equation to calculate the pressure:
P = (nRT) / V
P = (22.0 mol * R * 320 K) / 0.00022 m³
The ideal gas constant (R) is approximately 8.314 J/(mol•K), so substituting this value in:
P = (22.0 * 8.314 J/(mol•K) * 320 K) / 0.00022 m³
Now, we need to convert the pressure from Pascals (Pa) to mmHg. The conversion factor is:
1 mmHg = 133.322 Pa
Multiplying the pressure by this conversion factor gives us the answer in mmHg:
P_mmHg = P * (1 mmHg / 133.322 Pa)
By substituting the value of P into this equation, we can find the pressure in mmHg.