Identify the relative molar amounts of the species in 0.10 M NaBr(aq).
NaBr, Na+, Br-, H3O+, OH-, H2O
To identify the relative molar amounts of the species in an aqueous solution of NaBr, we need to consider the dissociation of NaBr in water.
NaBr is a strong electrolyte, which means it completely dissociates into its constituent ions, Na+ and Br-, in water. Therefore, we can determine the relative molar amounts by looking at the stoichiometry of the dissociation reaction.
The dissociation equation for NaBr in water is:
NaBr(aq) → Na+(aq) + Br-(aq)
From this equation, we can determine that for every one mole of NaBr that dissolves, one mole of Na+ ions and one mole of Br- ions are produced.
Hence, the relative molar amounts of the species in 0.10 M NaBr(aq) are as follows:
- NaBr: 0.10 M (since it is the initial concentration)
- Na+: 0.10 M
- Br-: 0.10 M
- H3O+: Not present in this particular solution
- OH-: Not present in this particular solution
- H2O: Not included in the list as it is the solvent
It's important to note that the concentrations provided here assume complete dissociation of NaBr in water.