What is molarity of propanol, C3H7OH, when 60. mL propanol is mixed with enough H2O to make a final volume of 100. mL?
The MW of propanol = 60.11 g/mol and the density of propanol = 0.804 g/mL.
g propanol = volume x density
mols propanol = grams/molar mass
M propanol = mols/L solution. which is 0.100 L.
Thanks!
To find the molarity of propanol (C3H7OH) in the solution, we need to determine the number of moles of propanol and the volume of the solution.
Step 1: Calculate the mass of propanol.
Mass of propanol = volume x density
Mass of propanol = 60 mL x 0.804 g/mL = 48.24 g
Step 2: Convert the mass of propanol to moles.
Number of moles = mass / molar mass
Number of moles = 48.24 g / 60.11 g/mol = 0.802 mol
Step 3: Calculate the volume of the solution.
The final volume of the solution is 100 mL.
Step 4: Calculate the molarity.
Molarity = number of moles / volume of solution (in liters)
Molarity = 0.802 mol / 0.1 L = 8.02 M
Therefore, the molarity of propanol in the solution is 8.02 M.
To find the molarity of propanol in the given solution, we need to calculate the number of moles of propanol present in the solution and then divide it by the final volume of the solution (in liters).
Step 1: Calculate the mass of propanol in the solution.
Mass = volume x density
Mass of propanol = 60 mL x 0.804 g/mL = 48.24 g
Step 2: Convert the mass of propanol into moles.
Number of moles = mass / molar mass
Molar mass of propanol (C3H7OH) = (3 x atomic mass of Carbon) + (8 x atomic mass of Hydrogen) + atomic mass of Oxygen
= (3 x 12.01 g/mol) + (8 x 1.008 g/mol) + 16.00 g/mol
= 60.11 g/mol
Number of moles of propanol = 48.24 g / 60.11 g/mol ≈ 0.803 mol
Step 3: Calculate the molarity.
Molarity = number of moles / volume (in liters)
Volume = 100 mL = 100 mL / 1000 mL/L = 0.1 L
Molarity of propanol = 0.803 mol / 0.1 L ≈ 8.03 M
So, the molarity of propanol in the solution is approximately 8.03 M.