The elements lithium and oxygen react explosively to from lithium oxide (Li2O). How much lithium oxide will form if 3.03 mol of lithium react?
Answer in units of mol
The elements lithium and oxygen react explosively to form lithium oxide. How many moles of lithium oxide will form if 2 mol of lithium react ?
To find out how much lithium oxide will form when 3.03 mol of lithium reacts, we need to determine the stoichiometry of the reaction. From the balanced chemical equation:
4 Li + O2 → 2 Li2O
We can see that 4 moles of lithium react with 1 mole of oxygen to produce 2 moles of lithium oxide. Therefore, the molar ratio of lithium to lithium oxide is 4:2 or 2:1.
Since we have 3.03 mol of lithium, we can use this ratio to calculate the amount of lithium oxide formed:
3.03 mol Li * (2 mol Li2O / 4 mol Li) = 1.52 mol Li2O
Therefore, when 3.03 mol of lithium reacts, 1.52 mol of lithium oxide will form.
To find the amount of lithium oxide formed if 3.03 mol of lithium react, we need to determine the stoichiometry of the reaction. The balanced chemical equation for the reaction between lithium and oxygen to form lithium oxide is:
4Li + O2 -> 2Li2O
From the balanced equation, we can see that 4 moles of lithium react with 1 mole of oxygen to produce 2 moles of lithium oxide.
To find the amount of lithium oxide formed, we can use the mole ratio between lithium and lithium oxide.
3.03 mol of lithium x (2 mol Li2O / 4 mol Li) = 1.515 mol of lithium oxide
Therefore, if 3.03 mol of lithium react, 1.515 mol of lithium oxide will be formed.
2Li + O2 ==> Li2O
3.03 mol Li x (1 mol Li2O/2 mols Li) = 3.03 x 1/2 = ? mols Li2O
If you want grams, then g Li2O = mols x molar mass.