How many grams do 5.8×10 24 atoms of argon
weigh?
Answer in units of g
Molar mass of Ar = 39.948 g/mol according to convertunits. com
a mole is equal to 6.022 * 10^23
therefore, 5.8 * 10^24 / 6.022 * 10^23 * 39.948 is your weight.
zazaza
To calculate the weight of 5.8×10^24 atoms of argon, we need to find the molar mass of argon and then multiply it by the number of atoms provided.
The molar mass of argon (Ar) is approximately 39.95 g/mol.
We can now calculate the weight using the following steps:
1. Calculate the number of moles:
Number of moles = Number of atoms / Avogadro's number
Number of moles = (5.8×10^24 atoms) / (6.022×10^23 atoms/mol)
Number of moles ≈ 9.63
2. Multiply the number of moles by the molar mass of argon:
Weight = Number of moles * Molar mass
Weight = 9.63 mol * 39.95 g/mol
Weight ≈ 385 g
Therefore, 5.8×10^24 atoms of argon weigh approximately 385 grams.
To find the weight of 5.8 × 10^24 atoms of argon, you need to know the molar mass of argon and use Avogadro's number.
First, find the molar mass of argon from the periodic table. The molar mass of argon (Ar) is approximately 39.95 g/mol.
Next, use Avogadro's number (6.022 × 10^23 atoms/mol) to convert the number of atoms into moles. Divide the given number of atoms (5.8 × 10^24 atoms) by Avogadro's number:
5.8 × 10^24 atoms / 6.022 × 10^23 atoms/mol
This calculation gives you the number of moles of argon.
Then, multiply the number of moles of argon by the molar mass of argon to obtain the weight in grams:
Number of moles × Molar mass = Weight
Plugging in the values:
(5.8 × 10^24 atoms / 6.022 × 10^23 atoms/mol) × (39.95 g/mol)
This calculation will give you the weight of 5.8 × 10^24 atoms of argon in grams.