The dimensions of rectangle B are twice the dimensions of rectangle A. The area of rectangle B is 200 cm2.
What is the area of rectangle A?
xy = 200
2x*2y = 4xy
4 * 200 = 800
Woops misread question.
It would be 200/4 = 50cm^2
To find the area of rectangle A, since the dimensions of rectangle B are twice the dimensions of rectangle A, we need to find the dimensions of rectangle A.
Let's assume that the length of rectangle A is "l" cm and the width of rectangle A is "w" cm.
According to the given information, the dimensions of rectangle B are twice the dimensions of rectangle A. So, the length of rectangle B will be 2*l cm and the width of rectangle B will be 2*w cm.
The formula for the area of a rectangle is:
Area = length * width
Therefore, the area of rectangle A will be:
Area of A = l * w
And the area of rectangle B will be:
Area of B = 2*l * 2*w = 4*l * w
Given that the area of rectangle B is 200 cm², we can write:
4*l * w = 200
To find the area of rectangle A, we need to solve this equation by expressing one variable in terms of the other.
Let's isolate one variable. Dividing both sides of the equation by 4, we get:
l * w = 200 / 4
l * w = 50
Now, we can substitute the value of "l * w" into the formula for the area of rectangle A:
Area of A = 50 cm²
Therefore, the area of rectangle A is 50 cm².