What is the concentration when 60.0 mL of a 9.00 M HCl solution is diluted to 1.170 liters? and how do you solve this problem?
To determine the concentration of a solution after dilution, you can use the formula:
C1V1 = C2V2
Where:
C1 = Initial concentration of the solution
V1 = Initial volume of the solution
C2 = Final concentration of the solution
V2 = Final volume of the solution
In this case, we have:
C1 = 9.00 M (initial concentration)
V1 = 60.0 mL (initial volume)
C2 = ? (final concentration, what we're trying to find)
V2 = 1.170 liters (final volume)
To solve the problem, we can rearrange the formula to solve for C2:
C2 = (C1 * V1) / V2
Now, let's plug in the values and calculate:
C2 = (9.00 M * 60.0 mL) / 1.170 liters
First, we need to convert the initial volume (V1) from milliliters to liters by dividing it by 1000:
V1 = 60.0 mL / 1000 mL/L = 0.060 liters
Now, plug the values into the formula:
C2 = (9.00 M * 0.060 L) / 1.170 L
C2 = 0.54 M
Therefore, the concentration of the solution after dilution is 0.54 M.