If a pendulum is 30 feet long what is the period of the pendulum in seconds with function l = 0.81t^2
To find the period of a pendulum, we can start by using the given function:
l = 0.81t^2
In this equation, "l" represents the length of the pendulum and "t" represents the period. We are given that the length of the pendulum is 30 feet:
30 = 0.81t^2
To solve for "t", we need to isolate the variable on one side of the equation. Let's rearrange the equation:
0.81t^2 = 30
Divide both sides of the equation by 0.81:
t^2 = 30 / 0.81
t^2 ≈ 37.037
To solve for "t", we take the square root of both sides:
t ≈ √37.037
So, the period of the pendulum is approximately equal to the square root of 37.037. To find the value in seconds, we need to evaluate this square root using a calculator:
t ≈ √37.037 ≈ 6.08 seconds (rounded to two decimal places)
Therefore, the period of the pendulum is approximately 6.08 seconds.