The concentration of saturated NaOH is 50.0% w/w and the density is 1.52 g/mL. If exactly 8.50 mL were diluted to 1.000 L, what would be the concentration?
To find the final concentration after dilution, we can use the relationship:
C1V1 = C2V2
Where:
C1 = initial concentration
V1 = initial volume
C2 = final concentration
V2 = final volume
Given that the initial volume is 8.50 mL and the final volume is 1.000 L, we can substitute these values into the equation:
(50.0% w/w) * (8.50 mL) = C2 * (1.000 L)
First, let's calculate the amount of NaOH in grams in the initial solution:
Amount of NaOH = (50.0% w/w) * (8.50 mL) * (1.52 g/mL)
Next, we need to convert the amount of NaOH to moles using the molar mass of NaOH which is approximately 40 g/mol:
Amount of NaOH (in moles) = (Amount of NaOH in grams) / (Molar mass of NaOH)
Finally, we can substitute the values into the equation to find the final concentration:
C2 = [(50.0% w/w) * (8.50 mL) * (1.52 g/mL)] / [(Amount of NaOH in grams) / (Molar mass of NaOH) * (1.000 L)]
By performing the calculations, we can find the final concentration after dilution.