will smeone please help me solve this question.
Simplify the expression. Write your answer in the lowest terms ans leave it in factored form.
__3y__ + ___4__
y(4y-1) 4y-1
I will assume you meant
(3y)/(y(4y-1)) + 4/(4y-1)
so the LCD = y(4y-1)
= (3y + 4y)/(y(4y-1))
= 7y/(y(4y-1))
yes. thanks so much
cancel the y's, so
answer is 7/(4y-1)
agree, Wayne is right, I should have finished it
To simplify the given expression and leave it in factored form, we can follow these steps:
Step 1: Combine the fractions over a common denominator.
The expression is:
(3y / y(4y-1)) + (4 / 4y - 1)
Since the second fraction already has a denominator of 4y - 1, we only need to adjust the first fraction to have the same denominator.
Multiplying the numerator and denominator of the first fraction by (4y - 1), we get:
(3y * (4y - 1) / y(4y - 1)) + (4 / 4y - 1)
Simplifying the numerator of the first fraction, we get:
(12y^2 - 3y / y(4y - 1)) + (4 / 4y - 1)
Step 2: Combine the fractions into a single fraction.
To add fractions, we need a common denominator. The common denominator in this case is y(4y - 1).
Combining the fractions, we get:
[(12y^2 - 3y) + (4y)] / y(4y - 1)
Simplifying the numerator by combining like terms, we have:
(12y^2 + y) / y(4y - 1)
Step 3: Factorize the numerator and denominator.
The numerator, 12y^2 + y, cannot be factored further.
The denominator, y(4y - 1), is already factored.
Therefore, the simplified expression in factored form is:
(12y^2 + y) / y(4y - 1)
Hence, the answer to the question is (12y^2 + y) / y(4y - 1).