find the sum of each finite arithmetic series 8+9+10+...+15

To find the sum of a finite arithmetic series, you can use the following formula:

Sn = (n/2) * (2a + (n-1)d)

where:
Sn = sum of the arithmetic series
n = number of terms
a = first term
d = common difference

In this case, the first term (a) is 8, the common difference (d) is 1, and we need to find the sum of the series from 8 to 15, which means there are 15 - 8 + 1 = 8 terms.

Plugging the values into the formula:

Sn = (8/2) * (2 * 8 + (8-1) * 1)
= 4 * (16 + 7)
= 4 * 23
= 92

Therefore, the sum of the series 8 + 9 + 10 + ... + 15 is 92.

To find the sum of a finite arithmetic series, we can use the formula:

Sn = (n/2)(a + l)

where:
- Sn represents the sum of the series
- n represents the number of terms in the series
- a represents the first term of the series
- l represents the last term of the series

In your case, the first term (a) is 8, and the last term (l) is 15. Since we are given the terms individually, we need to count the number of terms (n) to use in the formula.

To find the number of terms, we can subtract the first term from the last term and then add 1:

n = (l - a) + 1

Substituting the values we have:

n = (15 - 8) + 1
n = (7) + 1
n = 8

Now, we can use the formula to find the sum (Sn):

Sn = (n/2)(a + l)
Sn = (8/2)(8 + 15)
Sn = (4)(23)
Sn = 92

Therefore, the sum of the series 8 + 9 + 10 + ... + 15 is 92.

8+9+10+11+12+13+14+15 = ?