the pressure in a 10.0 L cylinder is raised from 483 mm Hg to 762 mm Hg. What is the new volume?
p1v1 = p2v2
I don't understand what it is i have to do
It isn't that complicated. I gave you a formula and you are to substitute the numbers into the formula. There will always be one item in the formula not given and you solve for that.
pressure1 x volume 1 = pressure2 x volume2
pressure 1 = 483 mm
volume 1 = 10 L
pressure 2 = 762 mm
volume 2 = unknown
So 483 x 10 = 762 x v2
solve for v2.
thank you very much
6.34 L
To find the new volume, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when temperature is held constant.
Boyle's Law formula: P1 * V1 = P2 * V2
where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
Given values:
P1 = 483 mm Hg
V1 = 10.0 L
P2 = 762 mm Hg (new pressure)
Now, let's solve for V2:
P1 * V1 = P2 * V2
Substituting the given values:
483 mm Hg * 10.0 L = 762 mm Hg * V2
Now, solve for V2:
V2 = (483 mm Hg * 10.0 L) / 762 mm Hg
V2 = 4830 mm L / 762
V2 ≈ 6.34 L (rounded to two decimal places)
Therefore, the new volume of the cylinder is approximately 6.34 L.