Am I missing something here.
They way I read this is that the answer is already given 9.5m. or are they after the angle of the ground to guy wire?
The guy wire is 13.4m long. It supports a vertical power pole. The wire is fastened to the ground 9,5m from the base of the 8.7m tall pole . Calculate the measure of guy wire and the ground.
Based on the given information, it seems like you are asking about the angle between the guy wire and the ground. To calculate this angle, you can use the concept of right triangles and trigonometry.
To find the measure of the guy wire, you can use the Pythagorean theorem. In this case, the guy wire, the vertical pole, and the distance from the ground to the wire form a right triangle. According to the theorem, the square of the hypotenuse (the guy wire) is equal to the sum of the squares of the other two sides.
Let's denote the measure of the guy wire as x. Using the Pythagorean theorem, we can set up an equation:
x^2 = (8.7m)^2 + (9.5m)^2
Simplifying the equation:
x^2 = 75.69m^2 + 90.25m^2
x^2 = 165.94m^2
Taking the square root of both sides of the equation:
x = √(165.94m^2)
x ≈ 12.88m
So, the measure of the guy wire is approximately 12.88m.
To find the angle between the guy wire and the ground, you can use the inverse trigonometric function tangent (tan). The formula is:
tan(angle) = opposite/adjacent
In this case, the angle you're looking for is the angle between the guy wire and the ground. The opposite side is the height of the pole (8.7m) and the adjacent side is the distance from the ground to the wire (9.5m).
So, the equation becomes:
tan(angle) = 8.7m/9.5m
To find the angle, we need to take the inverse tangent (arctan) of both sides of the equation:
angle = arctan(8.7m/9.5m)
angle ≈ 41.77°
Therefore, the measure of the guy wire is approximately 12.88m, and the angle between the guy wire and the ground is approximately 41.77°.