What is the value of t in the solution to this systems of linear equations?
2s – 3t = –1
3s – 4t = 0
a)–5
b)3
c)-7/3
d)4
do it the same way as I showed you when you posted as joe
i got 8s-12t=-1
and
9s-12t=0
i don't get how you subtract this?
To find the value of t in the solution to the system of linear equations, we can use the method of substitution or elimination. Let's use the method of elimination:
Given equations:
2s – 3t = –1 ...(1)
3s – 4t = 0 ...(2)
To eliminate one variable, we need to multiply the equations by a suitable number so that the coefficients of either 's' or 't' in both equations become the same.
Let's multiply equation (1) by 4 and equation (2) by -3:
8s - 12t = -4 ...(3)
-9s + 12t = 0 ...(4)
Now, add equations (3) and (4) together to eliminate the 't' variable:
(8s - 12t) + (-9s + 12t) = -4 + 0
-s = -4
Divide both sides of the equation by -1:
s = 4
Now substitute the value of s in either equation (1) or (2). Let's use equation (2):
3(4) - 4t = 0
12 - 4t = 0
Subtract 12 from both sides of the equation:
-4t = -12
Divide both sides of the equation by -4:
t = 3
Therefore, the value of t in the solution to the system of linear equations is 3. Hence, the correct answer is (b) 3.