Jill screams and hears her echo 4.4 seconds later. How far from the canyon wall is she if the air temperature is 25 degree C?

2*distance=velocitysound*4.4

figure the velocity of sound at 25C

To determine the distance between Jill and the canyon wall, we need to consider the speed of sound in air and the time it takes for the echo to reach her.

The speed of sound in dry air at a temperature of 25 degrees Celsius is approximately 343 meters per second.

Now, let's use the fact that sound travels at a constant speed to calculate the distance. We know that the time it takes for Jill to hear her echo is 4.4 seconds.

Since sound has to travel from Jill to the canyon wall and back to Jill, the total distance traveled is twice the distance between Jill and the canyon wall.

Using the formula: Distance = Speed x Time, the total distance traveled will be:

Distance = 2 x (Speed of sound) x (Time taken)

Plugging in the values:

Distance = 2 x 343 m/s x 4.4 s

Distance = 3016.4 meters

Therefore, Jill is approximately 3016.4 meters away from the canyon wall.