Jill screams and hears her echo 4.4 seconds later. How far from the canyon wall is she if the air temperature is 25 degree C?
2s=vt
s=vt/2=345•4.4/2=759 m
Vs= 331.5m/s + (0.6 * 25c) = 346.5m/s
D=Vsound * t/2
D= 346.5 m/s * 4.4sec/2 = 762.3 m
To determine how far Jill is from the canyon wall, we need to calculate the time it takes for sound to travel from Jill to the canyon wall and back to Jill (round trip), and then use this time to calculate the distance.
The speed of sound in air depends on the air temperature. A formula commonly used to calculate the speed of sound in air is:
v = 331.4 + 0.6 * t
Where:
v is the speed of sound in meters per second
t is the air temperature in degrees Celsius
Given that the air temperature is 25 degrees Celsius, we can substitute t = 25 into the formula to find the speed of sound in air:
v = 331.4 + 0.6 * 25
v = 331.4 + 15
v = 346.4 m/s
Now, we can calculate the distance by multiplying the speed of sound by the time taken for the echo to return (round trip). In this case, it is 4.4 seconds:
distance = speed of sound * time
distance = 346.4 * 4.4
distance ≈ 1522.96 meters
Therefore, Jill is approximately 1522.96 meters away from the canyon wall.