A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. How far did the ball travel before it hit the ground? Round the answer to the nearest meter.

A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees at a speed of 26 m/s. How far did the ball travel before it hit the ground? Round the answer to the nearest meter.

R = v^2/g sin 2θ

plug in v=26, θ=30° and g=9.8

rgth

To calculate the distance the ball traveled before hitting the ground, we need to use the equations of motion and break down the initial velocity into horizontal and vertical components.

The horizontal component of the initial velocity is given by Vh = V * cos(theta), where V is the magnitude of the initial velocity (26 m/s) and theta is the launch angle (30 degrees).

Thus, Vh = 26 m/s * cos(30 degrees) = 26 m/s * √3/2 ≈ 22.5 m/s.

The vertical component of the initial velocity is given by Vv = V * sin(theta), where V is the magnitude of the initial velocity (26 m/s) and theta is the launch angle (30 degrees).

Thus, Vv = 26 m/s * sin(30 degrees) = 26 m/s * 1/2 = 13 m/s.

Now, we need to find the time it takes for the ball to hit the ground. The vertical motion of the ball can be described by the equation:

H = Vv0 * t + (1/2) * g * t^2,

where H is the height (which is 0 when the ball hits the ground), Vv0 is the initial vertical velocity (13 m/s), g is the acceleration due to gravity (9.8 m/s^2), and t is the time.

Setting H to 0, we can solve the equation for t:

0 = 13 m/s * t + (1/2) * (9.8 m/s^2) * t^2.

This equation is a quadratic equation in terms of t, which we can solve using the quadratic formula or factoring. Solving the equation, we find two possible values for t: t = 0 or t ≈ 1.348 seconds.

Since we're interested in the time it takes for the ball to hit the ground, we can discard the solution t = 0 (which corresponds to the starting time). Thus, the ball takes approximately 1.348 seconds to hit the ground.

Now, we can calculate the horizontal distance the ball traveled:

Distance = Vh * t = 22.5 m/s * 1.348 s ≈ 30.3 meters.

Therefore, the ball traveled approximately 30 meters before hitting the ground.