HOW YOU CAN PREPAIR 1M OF SODIUM CHROLIDE IN 250CMCUBE
To prepare 1M of sodium chloride (NaCl) in 250 cm³ of solution, you will need to follow these steps:
1. Determine the molecular weight of sodium chloride (NaCl). Sodium (Na) has an atomic weight of 22.99 g/mol, and chlorine (Cl) has an atomic weight of 35.45 g/mol. Adding these together gives a molecular weight of NaCl as 58.44 g/mol.
2. Calculate the amount of sodium chloride (in grams) required to prepare 1 mole (1M) of the solution. Since the molecular weight of NaCl is 58.44 g/mol and you want 1 mole of NaCl, you will need 58.44 grams of NaCl.
3. Convert the given volume from cubic centimeters (cm³) to liters (L), as the molarity of a solution is expressed in moles per liter. Since 1 L is equal to 1000 cm³, 250 cm³ is equal to 0.25 L.
4. Calculate the concentration of the sodium chloride solution by dividing the grams of NaCl required by the volume of the solution in liters. In this case, dividing 58.44 g by 0.25 L gives you 233.76 g/L.
Therefore, to prepare 1M of sodium chloride in 250 cm³ (0.25 L) of solution, you will need to dissolve 58.44 grams of sodium chloride in the given volume of water or solvent.