A diagonal of a square parking lot is 75 meters.Find to the nearest meter, the length of a side of a lot
solve x^2 +x^2 = 75^2
2x^2 = 5625
x^2 = 5625/2
x = √(5625/2) = ....
To find the length of a side of a square parking lot, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, where the two shorter sides are called legs and the longest side is called the hypotenuse, the sum of the squares of the two legs is equal to the square of the hypotenuse.
In this case, the diagonal of the square parking lot is the hypotenuse, and the length of each side of the square is the legs.
Let's call the length of each side of the square parking lot "s".
According to the Pythagorean theorem, we have:
s^2 + s^2 = 75^2
2s^2 = 75^2
Dividing both sides by 2:
s^2 = 75^2 / 2
Taking the square root of both sides:
s = √(75^2 / 2)
Using a calculator, we can find that s is approximately 53.03 meters.
Rounding to the nearest meter, the length of each side of the parking lot is 53 meters.
To find the length of a side of the square parking lot, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides.
In this case, the hypotenuse is the diagonal of the square parking lot, which is given as 75 meters. Let's assume that the length of each side of the square is "s" meters.
Using the Pythagorean theorem, we have:
s^2 + s^2 = 75^2
Simplifying the equation:
2s^2 = 75^2
Dividing both sides by 2:
s^2 = (75^2)/2
Taking the square root of both sides to solve for "s":
s = √((75^2)/2)
Using a calculator, we can find that s is approximately 53 meters (rounded to the nearest meter).
Therefore, the length of each side of the square parking lot, to the nearest meter, is 53 meters.