What will be the temperature of a 3.5 gram sample of carbon dioxide gas in a 2.5 liter container at .955 atm
n = grams/molar mass, then
Use PV = nRT
To determine the temperature of a sample of gas, we need to use the Ideal Gas Law equation:
PV = nRT
Where:
P = Pressure (in atm)
V = Volume (in liters)
n = Amount of gas in moles
R = Universal gas constant (0.0821 L·atm/(mol·K))
T = Temperature (in Kelvin)
In this case, we know the following values:
P = 0.955 atm
V = 2.5 liters
n = Given as 3.5 grams of carbon dioxide (CO2)
To find the amount of gas in moles, we need to use the molar mass of carbon dioxide (CO2), which is approximately 44 g/mol.
n = mass / molar mass
n = 3.5 g / 44 g/mol
Now we can calculate the number of moles:
n = 0.0795 mol (rounded to 4 decimal places)
Now, rearranging the Ideal Gas Law equation to solve for T:
T = PV / (nR)
Substituting the values we know:
T = (0.955 atm) * (2.5 L) / (0.0795 mol) * (0.0821 L·atm/(mol·K))
Performing the calculations:
T ≈ 303.35 K
Therefore, the temperature of the 3.5 gram sample of carbon dioxide gas in the 2.5 liter container at 0.955 atm is approximately 303.35 Kelvin.