Pythagorean Theorem

A rectanglar box is 9 in. wide, 11 in. tall, and 20 in. long. What is the diameter of the smallest circular opening through which the box will fit? If necessary, round to the nearest tenth of a centimeter.

Try to put it through the circle using the smaller end

that is, the 9 by 11 end
We need the diameter of that rectangle

x^2 = 9^2 + 11^2 = 202
x = √202 = appr 14.2

so the circle will have to be > 14.2

i like this

To find the diameter of the smallest circular opening through which the box will fit, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, we can consider the diagonal of the box as the hypotenuse of a right triangle. The width (9 in.), height (11 in.), and length (20 in.) of the box form the sides of the right triangle.

Let's name the width as side A, the height as side B, and the length as the hypotenuse C. According to the Pythagorean theorem,

A^2 + B^2 = C^2

Substituting the known values, we have:

9^2 + 11^2 = C^2

81 + 121 = C^2

202 = C^2

Now, we can find the value of C by taking the square root of both sides:

√202 = C

C ≈ 14.2 in. (rounded to the nearest tenth of an inch)

So, the diagonal (which is the diameter of the circular opening) is approximately 14.2 inches.

i hate math

A rectangular box is 9 cm ​wide, 9 cm ​tall, and 5 cm long. What is the diameter of the smallest circular opening through which the box will​ fit?

9,9,6

this is dumb