Use the molar volume to find the volume, in liters, of 6.40g of O2 at STP.
MolarmassO2=32g
volume=22.4*6.4/32
Well, before I jog your mind, let me remind you that O2 has a secret. It's a true gasbag! Now, for your question, have you heard of Avogadro's law? It states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules. Lucky for us, the molar volume is your ticket to find the volume!
So, we'll start by determining the number of moles of O2. Since molar mass is equal to molar mass (who would've guessed?), we divide the mass of O2 (6.40g) by its molar mass (32.00g/mol).
That gives us 0.20 moles of O2 (6.40g/32.00g/mol). Now, since you want the volume in liters, we apply the molar volume at STP, which is approximately 22.4 L/mol.
Multiplying the number of moles (0.20 mol) by the molar volume (22.4 L/mol), we get a grand total of 4.48 L. Voila! That's the volume of 6.40g of O2 at STP.
To find the volume of a gas at STP using the molar volume, you can use the following steps:
Step 1: Determine the molar mass of O2 molecule.
The molar mass of O2 is 32.00 g/mol. This value can be determined by adding up the atomic masses of the two oxygen atoms.
Step 2: Calculate the number of moles of O2.
To calculate the moles, use the formula:
moles = mass / molar mass
Thus, moles of O2 = 6.40 g / 32.00 g/mol = 0.20 mol.
Step 3: Use the molar volume at STP to find the volume.
The molar volume of a gas at STP is 22.4 L/mol.
So, the volume of 0.20 mol of O2 is:
volume = moles * molar volume
volume = 0.20 mol * 22.4 L/mol = 4.48 L.
Therefore, the volume of 6.40 g of O2 at STP is 4.48 liters.
To find the volume of a gas at STP (Standard Temperature and Pressure), we can use the concept of molar volume. The molar volume is the volume occupied by one mole of any gas at STP, which is exactly 22.4 liters.
To find the volume of 6.40g of O2 at STP, we need to follow a few steps:
Step 1: Determine the molar mass of O2.
Oxygen (O) has a molar mass of approximately 16.00 g/mol. Since we have O2, we multiply the molar mass by 2.
Molar mass of O2 = 16.00 g/mol * 2 = 32.00 g/mol
Step 2: Convert the given mass of O2 (6.40g) to moles.
We can do this by dividing the mass by the molar mass.
Number of moles = 6.40g / 32.00 g/mol = 0.20 mol
Step 3: Use the molar volume formula to calculate the volume.
Since we have the number of moles, we can directly multiply it by the molar volume at STP.
Volume of O2 = 0.20 mol * 22.4 L/mol = 4.48 L
Therefore, the volume of 6.40g of O2 at STP is 4.48 liters.