Q) Calculate the new molarity of a 35mL sample of 0.450 M CaCl2 solution that is diluted with enough water to make 250 mL of solution.
A) M1V1 = M2V2
M1 = 0.450
M2 = ?
V1 = 0.035 L
V2 = 0.250 L
M2 = M1 X V1/V2
0.450 X (0.035L/0.250L) = 0.063
Did I set this up correctly and is my answer right? Thank you for helping!!
Yes, you have set up the equation correctly using the dilution formula M1V1 = M2V2.
To solve for M2, you rearranged the formula as M2 = M1 x V1/V2, where M1 is the initial molarity (0.450 M), V1 is the initial volume (35 mL or 0.035 L), and V2 is the final volume (250 mL or 0.250 L).
Substituting the values into the equation, we get M2 = 0.450 x (0.035 L / 0.250 L) = 0.063 M.
So, your answer is correct. The new molarity of the solution is 0.063 M.