Solve by the substitution method: 2x - 3y = 7 y = 3x - 7
2x+3y=8
-x-3y=what dose y and x =
-7−x−3y=−7
To solve this system of equations using the substitution method, we need to substitute the value of 'y' from the second equation into the first equation.
Given:
Equation 1: 2x - 3y = 7
Equation 2: y = 3x - 7
Step 1: Substitute y in Equation 1 with its value from Equation 2:
2x - 3(3x - 7) = 7
Step 2: Simplify the equation:
2x - 9x + 21 = 7
Step 3: Combine like terms:
-7x + 21 = 7
Step 4: Move constants to the other side:
-7x = 7 - 21
-7x = -14
Step 5: Divide by the coefficient of x to solve for x:
x = -14 / -7
x = 2
Step 6: Substitute the value of x into Equation 2 to find y:
y = 3(2) - 7
y = 6 - 7
y = -1
So, the solution to the system of equations is x = 2 and y = -1.
second equation into the first
2x - 3(3x-7) = 7
solve for x, then sub that back into the second.
Let me know what you got.
2x+3y=8
-x-3y=-7−x−3y=−7