How much work is done by the horizontal force F = 150 N on the 18 Kg block when the force pushes the block 5.0 M up along the 32 degree friction-less incline?

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  1. F*(horizontal distance moved)
    = 150*5.0*cos 32
    = 636 J

    You don't need the mass of the block to arrive at that answer. That is more than enough horizontal force to move the block up the frictionless ramp, so Kinetic Energy will increase.

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  2. I do get that answer also, but according to my textbook, the correct answer is

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  3. Anyi, the 636J is rounded to 640J due to significant figures.

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