A company has two printers. Printer A prints a pages per minute, and Printer B prints b pages per minute. When Printer A prints for 3 minutes and Printer B prints 5 minutes, a total of 70 pages are printed. When Printer A prints for 6 minutes and Printer B prints for 9 minutes, a total of 135 pages are printed. This situation is represented by this system of equations.
3a + 5b = 70
6a + 9b = 135
How many pages per minute does Printer A print?
F. 5
G. 11
H. 15
I. 30
Multiply Eq1 by -9, and multiply Eq2 by 5:
-27a - 45b = 630
+30a + 45b = 675
3a = 45
a = 15.
Correction: Eq1 = -630.
A printer prints 2 photos each minute. Let "P" be the number of photos printed in "M" minutes. Write an equation relating "P" to "M". then graph your answer.~~~~~~~(I cant graph the answer but I can do the equation. Kinda... Sometimes...Most of the time at least.)
ANSWER:2m=P
To find the number of pages per minute Printer A prints, we can solve the system of equations using the method of elimination or substitution. Let's use the method of substitution.
First, let's solve the first equation for a:
3a + 5b = 70
Subtract 5b from both sides:
3a = 70 - 5b
Divide both sides by 3 to isolate a:
a = (70 - 5b)/3
Now, substitute the value of a in the second equation with the expression we just found:
6((70 - 5b)/3) + 9b = 135
Multiply both sides by 3 to eliminate the denominator:
6(70 - 5b) + 27b = 405
Distribute and simplify:
420 - 30b + 27b = 405
Combine like terms:
-3b = -15
Divide both sides by -3:
b = 5
Now that we have the value of b, we can substitute it back into the first equation to find the value of a:
3a + 5(5) = 70
3a + 25 = 70
Subtract 25 from both sides:
3a = 45
Divide both sides by 3 to isolate a:
a = 15
Therefore, Printer A prints 15 pages per minute.
The answer is H. 15.