2 H2 + O2 -> 2 H2O
2 grams + 32 grams -> _ _ _ _ _ grams
how would the mass of water formed in the reaction compare to the mass of oxygen and hydrogen that reacts?
include types of change illustrated in the balanced equation.
explain the conversation of matter and determine the unknown amount of mass
explain the production of water.
To determine the unknown amount of mass of water formed in the reaction, we can start by using the balanced equation:
2 H2 + O2 -> 2 H2O
From the equation, we can see that 2 moles of H2 reacts with 1 mole of O2 to produce 2 moles of H2O.
Next, we need to calculate the molar masses of hydrogen (H2) and oxygen (O2). Hydrogen has an atomic mass of 1 gram/mole, and since we have 2 moles of H2, the total mass of hydrogen is 2 grams. Oxygen has an atomic mass of 16 grams/mole, and as we have 1 mole of O2, the total mass of oxygen is 32 grams.
So, combining the reactants, we have 2 grams of hydrogen and 32 grams of oxygen. Now, considering the law of conservation of matter, the total mass of the reactants should be equal to the total mass of the products.
In this reaction, the only product is water (H2O). Therefore, the total mass of the water formed should be equal to the total mass of the reactants. Hence, the unknown mass of water formed would be 2 grams + 32 grams = 34 grams.
Now let's analyze the types of changes illustrated in the balanced equation:
1. Combination reaction: The reactants (hydrogen and oxygen gas) combine to form a product (water).
2. Chemical change: The atoms rearrange their bonding and form new substances (H2O) with different chemical properties.
The production of water in this reaction occurs through a chemical change called a combustion reaction. Hydrogen and oxygen combine in the presence of heat or a spark, which causes the bonds between the atoms to break and reform, resulting in the formation of water molecules.
In conclusion, the mass of water formed in the reaction is 34 grams, which is equal to the combined mass of the hydrogen and oxygen reactants.