In a typical living cell, the electric potential inside the cell is 0.070 V lower than the electric potential outside the cell. The thickness of the cell membrane is 0.10µm. What is the magnitude and direction of the electric field (E) within the cell membrane?

700000

To find the magnitude and direction of the electric field (E) within the cell membrane, you can use the formula for electric field:

E = ΔV / d

Where:
E is the electric field
ΔV is the potential difference
d is the distance

In this case, the potential difference (ΔV) is given as 0.070 V and the distance (d) is given as 0.10 µm. However, before we can directly substitute these values into the formula, we need to convert the distance into meters.

1 µm = 1 × 10^(-6) m

So, the distance (d) in meters is:

d = 0.10 µm × (1 × 10^(-6) m/1 µm) = 0.10 × 10^(-6) m = 1 × 10^(-7) m

Now, we can substitute the values into the formula:

E = 0.070 V / (1 × 10^(-7) m)

Calculating this expression gives us the magnitude of the electric field within the cell membrane.