1) If the kelvin temperature of a gas sample in a steel tank increases to three times its original value , what will happen to the pressure?

I think It will increase. Is this correct?

By what factor does the gas pressure change?

2) A gas sample at a constant pressure shrinks to one fourth its initial volume. What will happen to its temperature?
I think It will decrease. Is this correct?

By what factor did the kelvin temperature of the gas change?

Please help, thanks

#1.

P1/T1 = P2/T2
T goes up 3x, P goes up 3x.

#2.
(P1V1)/T1 = (P2V2)/T2
P1 and P2 don't change.
V1 =1; V2 = 1/4
V goes down to 1/4; T goes down to 1/4
Check my thinking.

so all you need is that.

1) Yes, you are correct. According to Charles's law, the pressure of a gas at constant volume is directly proportional to its temperature. Therefore, if the Kelvin temperature of the gas sample increases to three times its original value, the pressure will also increase.

To determine by what factor the gas pressure changes, you can use the formula:

P2/P1 = T2/T1

Where P2 is the final pressure, P1 is the initial pressure, T2 is the final temperature, and T1 is the initial temperature.

Since the temperature increases by a factor of 3 (T2/T1 = 3), the pressure will also increase by the same factor.

2) Yes, you are correct. According to Boyle's law, at constant temperature, the volume of a gas is inversely proportional to its pressure. Therefore, if the gas sample shrinks to one fourth its initial volume, the pressure must increase to compensate, and as a result, the temperature will decrease.

To determine by what factor the Kelvin temperature of the gas changed, you can use the formula:

V1/V2 = T1/T2

Where V1 is the initial volume, V2 is the final volume, T1 is the initial temperature, and T2 is the final temperature.

Since the volume decreases to one fourth (V1/V2 = 1/4), the temperature must decrease by the same factor to maintain the equation's balance. Therefore, the Kelvin temperature of the gas changed by a factor of 1/4.

1) Yes, you are correct. According to Charles's Law, when the Kelvin temperature of a gas sample in a steel tank increases to three times its original value, the pressure will also increase. This happens because as the temperature increases, the average kinetic energy of the gas molecules increases, causing them to collide with the walls of the container more frequently and exert more force, leading to an increase in pressure.

To determine the factor by which the gas pressure changes, we can use the concept of proportionality. Since the temperature increases by three times, we can expect the pressure to increase by the same factor. Therefore, the factor by which the gas pressure changes will be 3.

2) Yes, you are correct again. According to Boyle's Law, when a gas sample is kept at a constant pressure and its volume decreases to one fourth its initial value, the temperature will decrease. This happens because as the volume decreases, the gas molecules get more confined, resulting in more frequent and intense collisions, which in turn leads to a decrease in the average kinetic energy and hence the temperature.

To determine the factor by which the Kelvin temperature of the gas changes, we can once again use the concept of proportionality. Since the volume decreases to one fourth, we can expect the temperature to decrease by the same factor. Therefore, the factor by which the Kelvin temperature of the gas changes will be 1/4.