Two parallel wires carry 1-A currents in unknown directions. The distance between the wires is 10-cm. What is the magnitude of the magnetic field B in Teslas at a point P located 6-cm away from the axis of one of the wires and 8-cm away from the axis of the other wire?
Details and assumptions
Uo(Mew)/{4*pi}= 10^{-7} H/m
To calculate the magnitude of the magnetic field at point P between the two parallel wires, you can use Ampere's law. Ampere's law relates the magnetic field around a closed curve to the electric current passing through the region enclosed by that curve.
Here are the steps to follow:
1. Determine the magnetic field created by one wire at point P. This can be done using the formula:
B1 = (μ0 * I1) / (2π * r1)
Where:
- B1 is the magnetic field created by one wire
- μ0 is the magnetic constant, which is equal to 10^(-7) H/m
- I1 is the current in the wire
- r1 is the distance from the axis of one wire to point P
Plugging in the values, we get:
B1 = (10^(-7) * 1) / (2π * 0.06)
2. Determine the magnetic field created by the other wire at point P. This can be done using the same formula as above, but with the current (I2) and distance (r2) of the other wire:
B2 = (10^(-7) * I2) / (2π * 0.08)
3. Calculate the total magnetic field at point P by adding the magnetic fields created by each wire:
B = B1 + B2
Note that the direction of the magnetic field created by each wire is determined by the right-hand rule. The direction of the currents in the wires and the relative positions of the wires will determine whether they add up or cancel each other out.
By following these steps and plugging in the given values, you should be able to calculate the magnitude of the magnetic field B at point P in Teslas.